tomtucson
New member
Since Nigel's been around I thought I would open up a thread for those who enjoy physics and math to analyze pressure washer related phenomena.
Todays question - How fast is the water going out the nozzle?
Speed (S) x Area (A) of nozzle = Volume (V) per unit time
S = V/A
So this volume can be converted to gallons and we should get the number
V x C = Gallons -> V = Gallons/C C = gallons/volume conversion factor
S = Gallons / C A given your gallons a minute and your nozzle area
I found that there is 231 cubic inches in a gallon so C = 1/231 gallons per cubic inch
So with area of my number 10 worn nozzle approximately 2/32" by 3/32" = 3/512" in sq
C = 1/231 in cubed
Gallons = 9 gpm
9 / (1/231) (3/512) = 354,816 in per minute = 29,568 ft per min = 492 feet per sec
Maybe there is a table of actual nozzle areas
And maybe there's a mistake here but it sounds like a reasonable number
Todays question - How fast is the water going out the nozzle?
Speed (S) x Area (A) of nozzle = Volume (V) per unit time
S = V/A
So this volume can be converted to gallons and we should get the number
V x C = Gallons -> V = Gallons/C C = gallons/volume conversion factor
S = Gallons / C A given your gallons a minute and your nozzle area
I found that there is 231 cubic inches in a gallon so C = 1/231 gallons per cubic inch
So with area of my number 10 worn nozzle approximately 2/32" by 3/32" = 3/512" in sq
C = 1/231 in cubed
Gallons = 9 gpm
9 / (1/231) (3/512) = 354,816 in per minute = 29,568 ft per min = 492 feet per sec
Maybe there is a table of actual nozzle areas
And maybe there's a mistake here but it sounds like a reasonable number