would you pay...

[Michael Cappa]

would you pay 3000 for a used Landa pw?
3000 at 5.5
generator model
Onan engine?

if so, check back often. I am picking it up monday and will have it for sale.

who's interested.

if this is in the wrong section Mike, let me know and I will move it.

 

[Hotwaterwizard]

Yes if it is a newer Hot Water Washer in good shape.

No if it is old.

The Onan Engine is HUGE and cold blooded.

I bought an Landa a while back for $300.
It needed so much work!
I kept it for 3 months then I sold it for $600 without even fixing it.

The frame was white and the engine was green.

The guy that bought it replaced the engine with a 20hp Honda For $1250 ,bought a new TS2021 General Pump $550 then he Stripped the frame and took it down and Powder coated it for $250. By the time he was done he spent $2800 but, the machine works like a new one

 

[Clean County PW]

I agree with the Wiz...as usual.

I also bought a used Landa a while back with a blown 24hp Onan engine for $500. I never had the time to restore the Landa PW

I ended up giving it to Ron Musgraves as a gift for him helping me get a Hydrotek trailer set-up delivered from Arizona to NY.

 

[Michael Cappa]

Not worried about the mechanical problems, that here is easily solved. But wiz, you have got me thinking. If it will take that much to heat all the water in the 14 gpm machine, I have something else to think about. I may just keep the landa for myself.

 

[Hotwaterwizard]

I have never seen a machine that puts out 14 gpm. It would need a bogger Engine than that!

Horsepower required: Flow (GPM) x Pressure (PSI) / 1460 = Electric Motor HP

Electric motor Horsepower x 1.5 = Gasoline Engine HP

Using the above formula and substituting 1100 for the 1460 arrives at an answer used by some manufacturers for Gasoline Engine HP. This is an 'Engineering Theoretical Performance' value derived from all components working perfectly according to theory. I do not find this to be realistic.

Using the above formula you can derive the following unknown values if you know part of the information.

Flow (GPM) = (HP / Pressure) x 1460
Pressure (PSI) = (HP / Flow) x 1460

For the correct nozzle size use the following:

Nozzle # = GPM x [Square root of (4000 / PSI)] A #4 nozzle will give you 4 GPM at 4000 PSI.

Therefore, GPM = Nozzle # x [Square root of (PSI / 4000)] and
PSI = (GPM / Nozzle #) Squared x 4000

On average you will lose 24 PSI per 100' run of 1/2" ID hose at 4 GPM; 34 PSI @ 5 GPM and 52 PSI at 6 GPM.

NEVER fall for Cleaning Units or Cleaning Performance numbers derived from GPM x PSI. This is not an accurate formula for comparison; this however is:

Reaction Force (in Pounds) = [GPM x (Square root of PSI)] / 18.92.

Therefore using a 2 GPM @ 1000 PSI unit as the start;

RF is (2 x 31.62) / 18.92 = 3.34#.

Double the flow to 4 GPM (4 x 31.62) / 18.92 = 6.69#.
Double the pressure but keep the flow (2 x 44.72) / 18.92 = 4.73#
Quadruple the pressure but keep the flow (2 x 63.25) / 18.92 = 6.69#

As I have said before FLOW IS OF MORE VALUE THAN PRESSURE, now you know why.

100,000 BTU will give a 140 degree F (60 C) heat rise per gallon of water. This is a Rule of Thumb as efficiencies of coils vary from manufacturer to manufacturer.

Forgot about water; it weighs 1 kilogram/ litre or 10 pounds/ Imperial gallon or 8.35 pounds/ US gallon.

The above information must be credited to Cat Pumps, Giant Pumps, Beckett Burners and my science teachers.

 

[Michael Cappa]

i think i am going to reduce the flow down to 10 gpm with two guns giving me 5 each, should be ok and also make the pump and engine last longer and not have to worry about the heat factor.

 

[Mike Hughes]

That sounds like a good idea...............easier on the water supply issue too. You'd burn through that 575 gallon tank before you knew it with 14.